frac{mass~(g)}{M_r} = \frac{9.125}{36.5} = 0.25\) Now look at the ratio of the reactants: 2 mol Al : 6 mol HCl (1 mol Al : 3 mol HCl) 0.1 mol Al : 0.3 mole HCl There are only 0.25 moles of HCl ...
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